16x^2-45x+26=0

Solution for 16x^2-45x+26=0 equation:

16x^2-45x+26=0

a = 16; b = -45; c = +26;
Δ = b2-4ac
Δ = -452-4·16·26
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-19}{2*16}=\frac{26}{32}
=13/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+19}{2*16}=\frac{64}{32}
=2
$